Question

The perimeter of a rectangle is 132m the length is 6m more than twice the width find the dimensions.

What is the length?
What is the width?

Answer 1

P=(l+W)*2
l=6+2W
132=(6+2W)+W)*2
132/2 =6+3W
66 -6 =3W
60/3 = W
20 = W
L = 6+(2*20)
L = 46

Answer 2

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Answer 3

What about the width?

Answer 4

width = 20
length=46