Question

The perimeter of a rectangle is 132m the length is 6m more than twice the width find the dimensions.


What is the width?

Answer 1

W=20

Answer 2

width =20
lenght = 46

Answer 3

I did answer

Answer 4

P=(l+W)*2
l=6+2W
132=(6+2W)+W)*2
132/2 =6+3W
66 -6 =3W
60/3 = W
20 = W
L = 6+(2*20)
L = 46

Answer 5

check:
P= (20 +46)*2
= 66*2
P = 132

Answer 6

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Answer 7

ty

Answer 8

yw