Question

The perimeter of a rectangle is 136inches. The length exceeds the width by 56 inches. Find the length and width

Answer 1

let width = x in
then length = x + 56 in

Perimeter = 2L + 2B

136 = 2(x + 56) + 2(x)
136 = 2x + 112 + 2x
136 - 112 = 4x
24/4 = x
x = 6

so width is = 6 in
length is 6 + 56 = 62 in

Answer 2

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