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evaluate the integral dx/sq root of x(1+x) dx.. can u detail it for me please
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\[\sqrt{x}(x+1)\] ? 1. Distribute x^(1/2) get (x^(1/2)+x^(3/2)) 2. Integrate normally get (2/3)x^(3/2)+(2/5)x^(5/2) 3. Check via derive get X^(3/2)+sqrt(x) = sqrt(x)(X+1) check
they gave me a different answer
Hmm... possible lemme check it on my TI really quick I did this in my head.
they said 2tan^-1sqroot x+c
Ti is giving me .4x^(5/2)+.666667x^(3/2) which is approx what I answered. Are you sure you asked the right question or are looking at the right answer
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