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OpenStudy (anonymous):
A group of ten women and twelve men must select a three person committee. How many committees of one woman and two men are possible? --- This is a counting method and probability problem.
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OpenStudy (anonymous):
There are 12 man, i choose one. We have 11 man left, and i choose another. The combinations are 12*11=132. Then i can choose a woman from the group of ten woman. Again 132*10=1320
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