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solve by using elimination 3r-5s=-34 5r+3s=34
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\[9r-15s=-102\]\[-25r-15s=-170\] If you subtract the bottom from the top, you are left with: \[34r=68\] so r=2. By plugging 2 in for r in the first equation: \[6-5s=-34\]\[-5s=-40\]\[s=8\]
ok where i get confused is how do I know which number to mult. each equation by
I got r=2 but I got stuck on s
so it would be (2,8)
Yes, all you have to do after getting one of the variables is substitute it into one of the given equations.
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thanks for the help
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