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Solve the equation: x^3+3x^2+5x+3=0
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we can see if it has any rational zeros we could let at + or -1 and + or - 3
x=-1
x = -1 , -1 -√2i , -1 + √2i http://www.wolframalpha.com/input/?i=x^3%2B3x^2%2B5x%2B3%3D0
Wait what's the rest though?
-1 | 1 3 5 3 | -1 -2 -3 _______________ 1 2 3| 0 since the remainder is 0 then x=-1 is a zero also x-1 is a factor just like like x^2+2x+3 is a factor of the polynomial above x^2+2x+3=0 solve this for x
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Sorry, CAS systems don't like i unless they are set up for it.
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