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solve then graph 5x>=to15
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divide 5>0 both sides x>=3
thanks angela210793 so it is not x>=to3 ans
\[x \ge3\] and let me graph it
The solution in graph is the area to the right-side of pointx=3 (inclusive). or all the numbers greater than equal to 3
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\[x \in]3;+\infty[\]
angela and a_clan thanks
yw :)
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