Question

find the equation of straight line which passes through the points(3,-5) (-3,5)

Answer 1

let's put the equation: y=ax+b,
we should find a and b,
the 1st point ( 3,-5) which means :
-5=a(3)+b
3a+b=-5.........(1)
the 2nd point is: (-3,5) which means:
5=a(-3)+b
-3a+b=5.........(2)
from (1):
b=-5-3a.....(3)
we replace it in (2):
-3a+(-5-3a)=5
-6a=10
thus: a=-10/6=-5/3
we replace in (3)
b= 0
so, the equation is/
\[y=(-5/3)x\]

Answer 2

hey thanks ...