Question

find the equation of a circle with centre as (3,5) and radius as 8 units

Answer 1

(x-3)^2+(y-5)^2=(8)^2
\[x ^{2}+y ^{2}-6x-10y-30=0\]

Answer 2

(x-3)\[\left( x-3 \right)^{2} +\left( y-5 \right)^{2} =8^{2}\]

Answer 3

u guys r making me confused ! which is true ?

Answer 4

\[\left( x-3 \right)^{2}+\left( y-5 \right)^{2}= 8^{2}\]