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OpenStudy (anonymous):
Write the equation whose roots are: 0.5, 1, -1, 2i
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OpenStudy (anonymous):
(x-0.5)(x-1)(x+1)(x-2i)=0
OpenStudy (anonymous):
Not quite, or something is missing. You cannot have a complex root without its complex conjugate root as well. Therefore, if nothing else, the answer would be \[(x-0.5)(x-1)(x+1)(x-2i)(x+2i)\]
OpenStudy (anonymous):
oh correct, i missed it, thanks:)
OpenStudy (anonymous):
No prob! :)
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