Question

find the equation of the circle passing through the point (-6,5), (-3,-4) and (2,1) what are the co-ordinates of the center of the circle?

Answer 1

consider the gen eqn of the circle
x^2+y^2+2gx+2fy+c=0, where g,f and c are constants to find out,
put the points in this eq
u will get three eqs in three unknows

Answer 2

ok ... thanks ..

Answer 3

can anyone give more explaination?

Answer 4

did u form the three eqs?

Answer 5

what r the values of g f and c ?

Answer 6

for(-6,5)
36+25-12g+10f+c=0
-12g+10f+c=-61

Answer 7

these r to determine by solving the eqs

Answer 8

for (-3,-4)
9+16-6g-8f+c=0
-6g-8f+c=-25

Answer 9

for (2,1)
4+1+4g+2f+c=0
4g+2f+c=-5

Answer 10

thanks

Answer 11

solve these eqs simultaneously to get g,f ,c

Answer 12

then centre is (-g,-f)
radius is sqrt(g^2+f^2-c)