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find the equation of the circle passing through the point (-6,5), (-3,-4) and (2,1) what are the co-ordinates of the center of the circle?
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consider the gen eqn of the circle x^2+y^2+2gx+2fy+c=0, where g,f and c are constants to find out, put the points in this eq u will get three eqs in three unknows
ok ... thanks ..
can anyone give more explaination?
did u form the three eqs?
what r the values of g f and c ?
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for(-6,5) 36+25-12g+10f+c=0 -12g+10f+c=-61
these r to determine by solving the eqs
for (-3,-4) 9+16-6g-8f+c=0 -6g-8f+c=-25
for (2,1) 4+1+4g+2f+c=0 4g+2f+c=-5
thanks
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solve these eqs simultaneously to get g,f ,c
then centre is (-g,-f) radius is sqrt(g^2+f^2-c)
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