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Mathematics 14 Online
OpenStudy (anonymous):

p2+2pq+q=1 ?

OpenStudy (anonymous):

is that q^2 also?

OpenStudy (anonymous):

(p+q)^2 =1 sqrt both sides p+q =1 so an infinite number of solutions is the question p^2+2pq+q^2=0

OpenStudy (anonymous):

I suppose it could also be a quadratic in p (with a not "nice" answer).

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