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OpenStudy (anonymous):
x+2y=6 (1) x=2-2y (2) What is the solution of the system?
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OpenStudy (anonymous):
is the ordered pair (2,-4) ??
OpenStudy (anonymous):
x+2y=6 (1) x=2-2y (2) Make 2y the subject in both 2y=6 - x(1) 2y = 2-x (2) Subtract [2] from [1] 0 = 4 (which we both know is nonesense) Therefore no real solutions as they are parallel lines (x values identical in both equations)
OpenStudy (anonymous):
oooh crap, well thanks lol
OpenStudy (anonymous):
i figured it out thank you :D
OpenStudy (anonymous):
niente!
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