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Equation: (x-4)/(x+2) = 7
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\[\frac{x-4}{x+2}*(x+2)=7(x+2)\] \[x-4=7x+14\] \[-4-14=7x-x\] -28=6x \[\frac{-28}{6}=\frac{6x}{6}\] \[x=\frac{-28}{6}=\frac{-14}{3}\]
right so x = ?
i don't understand the question? did i lose you somewhere?
just wondering if x = -28 -14 ---- = ---- 6 3 Is the final answer?
do you think is? i see a mistake up there -4-14 is not -28
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-4-14=7x-x -18=6x x=-18/6=-3
so x = -3?
do you see it says x=-18/6=-3?
yep
then why are you asking me what x= when i said x=-18/6=-3
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did you not understand how i got x?
i get it now just wasn't sure.
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