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Mathematics 20 Online
OpenStudy (anonymous):

evaluate the integral (lnx)^2/x dx

myininaya (myininaya):

let u=lnx du=1/x dx

myininaya (myininaya):

\[\int\limits_{}^{}u^2 du\]

myininaya (myininaya):

u^3/3+c (lnx)^3/3+c

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