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Find the equation for the line perpindicular to 7x-21y=39 that passes through the point (-3, 5). answer in y=mx+b. Simplify as much as possible, but leave iproper fractiobns. help please?
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21y = 7x - 39 y = (1/3) x - 13/3 slope of the perpendicular line = -1 / (1/3) = -3 using y-y1 = m(x-x1) y - 5 = -3(x+3) y = -3x -4
alright thank you again, sure it won't be the last
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