Question

How many gallons of a 80% antifreeze solution must be mixed 70 gallons of 15% antifreeze to get a mixture that is 70% anitfreeze?

Answer 1

LET number OF gallons OF 80% ANTIFREEZE be X
THEN 0 .15 * 70 + 0.80x = 0.70(x + 70)
0.8x - 0.70x = 49 - 10.5
0.1X = 38.5
x = 385 GALLONS

Answer 2

OK guy?

Answer 3

good looking out jimmy

Answer 4

thanx