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Find a formula for the inverse of the function. f(x) = sqrt (3 - 6x)
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(x^2 - 3)/ 6
y=sqrt{3-6x) solve this for x then replace x with f^(-1)(x) and replace y with x
wudnt it be \[\(x^\2\-\3\)\/\-\6\]
i think you will see that you will not get what khan has (he has some wrong signs)
wait, let me chk again!
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(x^2-3)/-6
thats right kehara
(x^2 - 3)/ -6
ok thanks
gj you get medal
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sorry, my bad!
its ok thanks
uw. & thnks for the medal.
myininaya are you still there?
I dont no how to find the inverse of this equation f(x) = sqrt (4-e^2x) I dont no how to solve for x because of the whole e thing
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