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OpenStudy (anonymous):
Prove: Sum from i=1 to n of i^3 = (n^2[n+1]^2)/4
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OpenStudy (anonymous):
This might help: http://answers.yahoo.com/question/index?qid=20101202063616AAqPOqn
OpenStudy (anonymous):
Thank you
OpenStudy (anonymous):
No problem :) Mathematical induction for the win xD
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