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calculate (f * g)' (3) f'(3)=-1 g'(3)=9
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Let f(x) = (3x^3)/((4-5x)^5) find the equation of the line tangent to the graph of f at x=2
what question is tht for what section?
chain rule problem 8
haven't done tht one yet
it's due now
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yeah i know
(fg)'=f'g+fg' (fg)'(3)=f'(3)g(3)+f(3)g'(3) =-g(3)+9f(3) anything else given is that f times g or f(g(x))
i assume it was times
yea it was times the f and g
thanks for the step by step too!!
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