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Mathematics 20 Online
OpenStudy (anonymous):

∫cosx/(1+sinx)

OpenStudy (anonymous):

u=sin(x)+1 du = cos(x)

OpenStudy (anonymous):

are u sure thats the answer??

OpenStudy (anonymous):

int du/u = int (1/u)du = log|u|+c = log|sin+1|+c

OpenStudy (anonymous):

that is correct

OpenStudy (anonymous):

its a standard result int f'(x)/ f(x) = ln f(x) +C

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