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Solve: (u + 3)(u - 3) = 8u
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u^2 - 9 = 8u u^2 -8u -9=0 u^2 - 9u + u -9=0
now solve it like i did
I got u = 0; u = -3; u = 3
?
youll get only 2 values
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u = -1; u = 9
now ur right
sorry I totally mess the first one up
Thanks !!!
using the fomula (a+b) (a-b) = a^2 - b^2 u get u^2 - (3)^2 = 8u => u^2 - 8u - 9 = 0 now u hv to factorise -9 into two factors A and B so that AB = -9 and A + B = -8 9 * -1 = -9 and 9 + (-1) = 8 => u^2 -9u + u - 9 =0 => u(u-9) +1(u-9) = 0 => (u+1) (u-9) = 0 for the product to b zero either of the factors has to b zero if u+1 = 0 => u = -1 if u-9 = 0 => u = 9
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