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Solve: x^2(x^4 + 16) = 8x^4
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take x^2 =t u get t(t^2 + 16) =8t^2
how did you get t?
just take x^2=y now y(y^2 +16)=8y^2 y{y^2-8y+16}=0 y{(y-4)^2}=0 y=0 or y-4=0 means y=0 or 4 means x^2=0 or 4 means x=0 or +2 or -2
thanks s but i still dont get this problem
wts wrong?
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why?
x = 0; x = -2; x = 4
i keep getting that
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