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Which value of p makes the midpoint of E(3p, 8) and F(9, 4p) fall on the y-axis? -5 -3 2 3 i got 2 am i right?..
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on the y axis x = 0 so 3p + 9=0 p=-3
THANK YOu (:
To find the midpoint of (x1,y1), (x2,y2) take the average of the coordinates... So, M=( (x1+x2)/2, (y1+y2)/2 ) Since you want it to fall on the y-axis, you want the x value of the midpoint to be 0. Substitute x1=3p and x2=9 into (x1+x2)/2=0 and solve for p.
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