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Solve: x2 – 26x + 48 = 0
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quadratic formula? complete the square? factor? probably factor is easiest
i dnt understand how to do it
two numbers whose product is 48 and whose sum is -26
x1=24, x2=2 by factorisation
you are going to write \[(x-a)(x-b)=0\] and you know that \[ab=48\] and \[a+b=26\]
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that if you can find those two numbers you win. not too hard in this case
thanks
x=24,2
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