Question

Classify:

(Sqrroot 1/2 )(sqrroot 1/8 )

Answer 1

is it \[\sqrt{1/2}) * \sqrt{1/8}\]

Answer 2

Hey Nany ????????????

Answer 3

Using the law
\[\sqrt{m}*\sqrt{n} = \sqrt{mn}\]
we get

\[\sqrt{1/2}*\sqrt{1/8} = \sqrt{1/16}\]

Answer 4

further using the law
\[\sqrt{m/n} = \sqrt{m}/\sqrt{n}\]
we get
\[\sqrt{1}/\sqrt{16} = 1/4\]