Question

The hypotenuse of a right triangle is 7 inches, and one of the legs is √13 inches. Find the length of the other leg.

Answer 1

\[7^2=x^2+\sqrt{13}^2\]
\[49=x^2+13\]
\[36=x^2\]
\[x=6\]

Answer 2

first line is pythagoras
\[h^2=a^2+b^2\] the plug in the numbers and solve for the one you do not know

Answer 3

A trig solution:\[7 \text{Cos}\left[\text{ArcSin}\left[\frac{\sqrt{13}}{7}\right]\right]=6 \]