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OpenStudy (anonymous):
The length of a rectangle is 3 more than twice the width. The area of the rectangle is 119 square inches. What are the dimensions of the rectangle? If x = the width of the rectangle, which of the following equations is used in the process of solving this problem? 2x2+ 3x - 119 = 0 3x2+ 3x - 119 = 0 6x2- 119 = 0
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