Question

How do I draw a phase portrait for:
y'=y^2(1-y^2)

Answer 1

Instead of x and y axes we have y' and y axes. Treat the given equation as an algebraic equation in y' and y and graph y' = y^2(1-y^2). I looks exactly like the graph of y = x^2(1 - x^2). The only thing that is different is the labels.

Answer 2

thanks