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cuberoot(x+2)=cuberoot(x-2)+2
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do you know?
yes i am trying on paper to see if i can solve it......
sorry friend, i am not sure about what i am arriving at, so i guess someone else might have to help you
i tried it , getting 0=x^2-2x+8, and thats not factorable, quite confused if im doing it right...
now im getting complex roots...
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actually I live in India Right now it is 2 AM in the morning and the brain is tired as I have been at it for many hours....
cool, what did you get though?
I now have +-2i
is anyone going to verify this?
\[x_1=\frac{10}{9}\sqrt{3}\,\,,\,\,x_2=-\frac{10}{9}\sqrt{3}\]
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