Question

What are the possible number of positive, negative, and complex zeros of f(x) = x6 + x5+ x4 + 4x3 – 12x2 + 12 ?

Answer 1

there are 6 possible zero's of x since the biggest exponent is 6, and for possitive negative - look at how many times the signs change from + to - or vice versa. That will give you the answer