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Find the limit for the given function. http://www.webassign.net/cgi-bin/symimage.cgi?expr=lim_%28x-%3E0%29%20text%28%20%29%20%28sin%282%20x%29%29%2F%28sin%288%20x%29%29
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0/0, well first l'hopital and you get 2*cos(2x) / 8*cos(8x)
and then put in 0 and tou get 2/8
there are other ways as well
Is L'Hospital's used for mostly everything in Calc? Everyone uses it, but we haven't used it yet.
Yeah, there is a way to manipulate it knowing that lim (sin 2x)/2x=1 and 8x/sin 8x =1. Multiply by (2x)(8x)/(2x)(8x)
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l'hopital is good way to settle things.. but works only by 0/0 and \[\infty /\infty\]
If you haven't got to L'hopital yet, you would be expected to use method I described above.
agree with chaguanas..
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