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Mathematics 19 Online
OpenStudy (anonymous):

A test shows that 10 out of 100 gadgets are defective. In a random sample of two gadgets are chosen, the probability that both are defective it is:

OpenStudy (amistre64):

10/100 * 10/100

OpenStudy (amistre64):

since the sample is less than 5% of the population; you work it as if there is replacement. ,1 * .1 = .01

OpenStudy (anonymous):

ok thank you

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