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A ball rebounds 7/8 as high as it bounces on the previous bounce and is dropped from a height of 8 feet. How high does it bounce on the fourth bounce and how far has it traveled after the fourth bounce?
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8*(7/8)^4
8(1+2(7/8) +2(7/8)^2+ 2(7/8)^3)
can you explain how you got this answer. I am so confused
on the first bounce it bounces 7/8th as high as 8 feet. on the second bounce, it boundes 7/8th as high as the previous time and so on. so the answer is 8(7/8)^4
is this a arithmetic sequence or geometric
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geometric
thank you
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