Question

Find an equation of the tangent line to the curve below at the point (0, 1).

http://www.webassign.net/cgi-bin/symimage.cgi?expr=y%20%3D%202%20%2F%20%281%20%2B%20e%5E%28-x%29%29

Answer 1

take the derivative of the function (dy/dx) to get the slope of the tangent.
substitute (x,y) = (0,1) in y = mx +b to get b in the equation of the tangent line at that point

Answer 2

f'(x)= -2*e^x

Answer 3

-2*e^0 = -2*1 = -2 (most likely)