Question

A softball is thrown up into the air. The ball's height in feet is modeled by the equation h(t) = -16t2 + 32t + 5.
h = height
t = time in seconds
Find the maximum height of the ball.

Answer 1

take derivative & = 0

Answer 2

h'=-32t+32=0
t=1 (sec)
put the value in original equation & find h(1)

Answer 3

If you're not a calculus student, you can find the answer by finding the vertex of the parabola at (-b/2a, f(-b/2a)). where a = -16, b = 32, and c = 5.