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Mathematics 19 Online
OpenStudy (anonymous):

A student has the following grades: 80, 76, 78, 83, 83. Find the variance of the grades.

OpenStudy (saifoo.khan):

mean?

OpenStudy (anonymous):

no the variance

OpenStudy (saifoo.khan):

V=[(x-xm)^2]/m

OpenStudy (anonymous):

the answer?

OpenStudy (saifoo.khan):

here xm is the mean of these values

OpenStudy (saifoo.khan):

lol, idk how top use the form

OpenStudy (anonymous):

first find the mean/average of 80,76,78,83,83 which is 80 second calculate the deviations from the mean of each data point: (80-80), (76-80), and so on next square these deviations: 0, 16, and so on sum these squares and divide by 5, the number of data points you now have the variance

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