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the square root of 2y-1 -3=0
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y = 2
\[\sqrt{2y-1}-3=0\] the options are no solution ; y=4 ; y=1 and y=5
oh
y=5
5
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Process is: \[\begin{align} \sqrt{2y - 1} - 3 &= 0\\ \sqrt{2y - 1} &= 3\\ \sqrt{2y - 1}^2 &= 3^2\\ 2y - 1 &= 9\\ 2y &= 10\\ y &= 5 \end{align}\]
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