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√3x+1= -4+ √5x-3
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is √3x+1 means only √3x or the whole √3x+1 i root
the whole 3x+1 square rooted
\[3x+1=(-4+(\sqrt{5x-3)})\] \[3x+1=16-8\sqrt{5x-3}+(5x-3)\] \[3x+1-16=5x-3-8\sqrt{5x-3}\] \[3x-15+3-5x=-8\sqrt{5x-3}\] \[-2x-12=-8\sqrt{5x-3}\] \[2x+12=8\sqrt{5x-3}\] \[(2x+12)^{2}=[8\sqrt{5x-3}]^{2}\] \[4x ^{2}+48x+144=64(5x-3)\] \[4x ^{2}-272x+336=0\]
you can try solving ahead on ur own
Thank you very much :)
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