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The area of a rectangle is given by A = x2 + 4x – 5. Find the value of x if the total area of the rectangle is equal to 7 square units. a) x = 1 b) x = 2 c) x = 7 d) x = 5
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Set A=7 and solve for x. \[x^{2}+4x-5=7\]\[x^{2}+4x-12=0\]\[(x+6)(x-2)=0\] Only one answer will make sense.
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