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OpenStudy (anonymous):
Solve: z2 + 2iz - 1 = 0
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OpenStudy (anonymous):
-1=i^2 z^2+2iz+i^2=0 (z+i)^2=0 z=-i
OpenStudy (anonymous):
see thats what i got but i thought i couldnt be negative :/
OpenStudy (anonymous):
see thats what i got but i thought 'i' couldnt be negative
OpenStudy (anonymous):
-i perfectly exists.
OpenStudy (anonymous):
thanks!! i was about to flip wheni kept reworking it and still got -i
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