absolute value of 3x-8 greaterthan or equal to 5 is........
two solutions
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OpenStudy (anonymous):
Just remember your absolute value rules..
\[\forall a,b \in \mathbb{R} \text{ and } b > 0,\ \ |a| > b \implies a > b \text{ or } a < -b\]
So in this case you have:
\[|3x -8| \ge 5\]
Which part of this relation is your a, and which is your b?
OpenStudy (keenan):
its dealing with inequalities
OpenStudy (anonymous):
I've written inequalities..
OpenStudy (anonymous):
Compare this:
\[|a| \ge b\]
To this:
\[|3x -8| \ge 5\]
Which part in your problem corresponds to the 'a' part and which corresponds to the 'b'?
OpenStudy (keenan):
a=3x-8, b=5 c= the value of x
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OpenStudy (anonymous):
There is no c..
OpenStudy (keenan):
then what is the value of x
OpenStudy (anonymous):
Ok, so if a is 3x - 8 and b is 5, and
\[|a| \ge b \implies a \ge b \text{ or } a \le -b\]
So can you write your two new inequalities using that formula and your a and b?
OpenStudy (keenan):
ok but how
OpenStudy (anonymous):
I just told you.
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OpenStudy (anonymous):
\[|a| \ge b\]
Implies two inequalities:
\[a \ge b\]
or
\[a \le -b\]