absolute value of 3x-8 greaterthan or equal to 5 is........ two solutions
Just remember your absolute value rules.. \[\forall a,b \in \mathbb{R} \text{ and } b > 0,\ \ |a| > b \implies a > b \text{ or } a < -b\] So in this case you have: \[|3x -8| \ge 5\] Which part of this relation is your a, and which is your b?
its dealing with inequalities
I've written inequalities..
Compare this: \[|a| \ge b\] To this: \[|3x -8| \ge 5\] Which part in your problem corresponds to the 'a' part and which corresponds to the 'b'?
a=3x-8, b=5 c= the value of x
There is no c..
then what is the value of x
Ok, so if a is 3x - 8 and b is 5, and \[|a| \ge b \implies a \ge b \text{ or } a \le -b\] So can you write your two new inequalities using that formula and your a and b?
ok but how
I just told you.
\[|a| \ge b\] Implies two inequalities: \[a \ge b\] or \[a \le -b\]
oh ok nevermind i got it
thank you
So what would your two inequalites be?
Join our real-time social learning platform and learn together with your friends!