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7x-9>2(x+4) -
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Distribute the 2, combine like terms and solve.
so you have to muliply 2 into x and 4 right
Yep.
2x+8 right
Correct. Then move all your x terms to one side and your non-x terms to the other side.
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(by adding/subtracting)
soit would be 7x-2x>9-8 -
7x-2x > 8 + 9 (the 9 was negative on the other side)
7x-9>2(x+4) x>17/5 5x>17 7x-9>2x+8
so its -9
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What is -9?
the answer is 7x-2x>-9+8\[7x-2x \ge-9+8\]
No. \[7x - 9 \ge 2(x+4)\]\[\implies 7x - 9 \ge 2x + 8\]\[\implies 7x -9 -2x \ge 2x +8 - 2x\]\[\implies 7x - 2x - 9 + 9\ge 8 + 9\]\[\implies 7x - 2x \ge 8 + 9\]\[\implies 5x \ge 17\]\[\implies x \ge \frac{17}{5}\]
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