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standard form of: (x)(x-3)(x-5)
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Distribute and combine like terms.
x(x-3)(x-5) x^3-8x^2+15x x((x-8)+15) where u can get x=0, 3, &5
(x)(x-3)(x-5)= \[x(x ^{2}-8x+15)\] \[x ^{3}-8x ^{2}+1\]
x(x-3)(x-5) x^3-8x^2+15x x((x-8)x+15) where u can get x=0, 3, &5
You won't get solutions.. it's not an equation.
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\[x ^{3}-8x ^{2}\+15]
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