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a basket contains 6 pieaces of paper numbered from 1 to 6. a hat contains the letter a,b,and c. if a blindfolded person picks a number and a letter,what is the probability that the number is even and the letter is a
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Well what is the probability that the number is even?
the probability of event1 AND event2 = p(event1) * p(event2)
since the basket and hat are disjoint; theres no need to confuse yourself over the probabilty event2 given event1 :)
6 pieaces =1,2,3,4,5,6, even = 2,4,6 3/6=1/2
yes; 1/2 for the first event; and for the next?
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I dont know next, becaause letter I don't get what is say
amistree u do next I don't know next
there are 3 total choices and 1 is an a :) 1/3
P(even#) * P(a) = (1/2) * (1/3) = (1/6)
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