a coin is loaded so that the probabilityof getting heads 3/4. if the coin is flipped twice,what is the probability of gettiing heads twiice
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OpenStudy (anonymous):
2/4 i think
OpenStudy (anonymous):
This is the same kind of problem as your other one.
The probability of getting heads the first time is?
OpenStudy (anonymous):
1/2
OpenStudy (anonymous):
No, the question specifically says that the coin is loaded so it's 3/4
OpenStudy (anonymous):
o
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OpenStudy (anonymous):
And on the second flip you still have another 3/4 chance of getting heads.
OpenStudy (anonymous):
6/8
OpenStudy (anonymous):
So the probability of getting both is the probability of the first, times the probability of the second.
OpenStudy (anonymous):
9/16
OpenStudy (anonymous):
Correct. Anytime you have 2 different events that both must occur you have to multiply the probability for each event together.
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OpenStudy (anonymous):
Same thing for the letters/numbers problem you were asking about before. It would be 3/6 chance of a number being even
1/3 chance of a letter being a
So probability of both would be 3/6 times 1/3 = 3/18 = 1/6