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Mathematics 21 Online
OpenStudy (anonymous):

Given the following cards, what is the probability of drawing a blue card, not replacing it, and then drawing another blue card?

OpenStudy (anonymous):

OpenStudy (amistre64):

well; 3 out of 5 are blue; which leaves 2 out of 4 for the next pick \[\frac{3}{5}*\frac{2}{4}=P(Blue\ and\ Blue)\]

OpenStudy (anonymous):

so, 3/10?

OpenStudy (amistre64):

yep :)

OpenStudy (anonymous):

thanks, you rock.

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