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The area of a rectangle is given by A = x2 + 4x – 5. Find the value of x if the total area of the rectangle is equal to 7 square units.
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\[7=x ^{2}+4x-5\]\[x ^{2}+4x-12=0\] (x+6)(x-2)=0 x=-6 x=2
verify by susbstitution \[A=2^{2}+4(2)-5=12-5=7\] Since it is asking for x we can also\[A=(-6)^{2}+4(-6)-5=36-24-5=7\]
This is not a dimension (the -6), so don't let it distract you.
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