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Mathematics 19 Online
OpenStudy (anonymous):

solve the following equation using the quadric formula 2x^2-15x-1=0

OpenStudy (anonymous):

\[x=\frac{15\pm\sqrt{223}}{4}\]

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

need the formula?

OpenStudy (anonymous):

x=15

OpenStudy (anonymous):

x=(15+~(233))/(4),(15-~(233))/(4)_x<Z>APPR<z>7.57,-0.07

OpenStudy (anonymous):

???

OpenStudy (anonymous):

\[x=15+\sqrt{233}/4, 15-\sqrt{233}/4\]

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